Question

can you give me the answer​

Answer 1

use the formula

padit badri prasad

har har bole

sona chandi tole

it will be easy for you to answer

use first letters of the line

it will be applied as pythagoras theorem

hope it helps!!!!!!

mark as brainliest

Answer 2

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$tan~ B = \frac {opposite~side}{adjacent~ side} = \frac {12}{9}$

$cos~B = \frac{adjacent~side}{hypotenuse} = \frac{20}{5} = \frac{4}{5}$

$tan~M = \frac {opposite~side}{adjacent~side}= \frac{8}{15}$

$sin~G = \frac {opposite~side}{hypotenuse} = \frac{32}{40}= \frac{4}{5}$

$tan~G = \frac {opposite~side}{adjacent~side} = \frac {15}{20} = \frac {3}{4}$

$cos~C = \frac {adjacent~side}{hypotenuse} = \frac{28}{35} = \frac {4}{5}$

$tan~X = \frac{opposite~side }{adjacent~side} = \frac {8}{15}$

$sin~O = \frac{opposite~side}{hypotenuse} = \frac{20}{52} = \frac {10}{26} = \frac {2}{13}$