Question

Can you guess her????
.
ABCD is a parallelogram such that AB = 2 AD
E is the midpoint of (AB) and F is the midpoint of [CD]
1) Prove that AEFD and BCFE are rhombuses.
2) Prove that triangle AFB is a right triangle.
HELP ​​

Answer 1

Let us draw a parallelogram ABCD Where F is the midpoint Of side DC of parallelogram ABCD

To prove : AEFD is a parallelogram

Proof Therefore ABCD

AB || DC

BC || AD

AB || DC

2

1

AB=

2

1

DC

AE = DF

Also AD || EF

Therefore ,AEFC is a parallelogram.

solution

Let us draw a parallelogram ABCD Where F is the midpoint Of side DC of parallelogram ABCD

To prove : AEFD is a parallelogram

Proof Therefore ABCD

AB || DC

BC || AD

AB || DC

2

1

AB=

2

1

DC

AE = DF

Also AD || EF

Therefore ,AEFC is a parallelogram.

solution