Question

can you guys help me with this ..​

Answer 1

1) 1/3x = 7

x = 7 × 3

x = 21

2)1/3x + 3 = 4

1/3x = 4-3

1/3x = 1

x= 3

3) 3 - 1/4y =2

-1/4y = 2-3

-1/4y = -1

y = -1 × 4/-1

y = 4

Answer 2

$\sf{Solution}$

Given :-

$\sf\dfrac{1}{3}$x = 7

$\sf\dfrac{1}{3}$x+3 = 4

3 - $\sf\dfrac{1}{4}$y = 2

Concept to know :-

If we find the value of x that should be satisfy with LHS = RHS

Lets do one by one !!

1) $\sf\dfrac{1}{3}$x = 7

$\sf\dfrac{x}{3}$ = 7

Do cross multiplication

x = 7 × 3

x = 21

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2) $\sf\dfrac{1}{3}$x+3 = 4

$\sf\dfrac{x}{3}$+3 = 4

Take LCM to the LHS

$\sf\dfrac{x+9}{3}$ = 4

Do cross multiplication

x + 9 = 3 (4)

x + 9 = 12

Transpose 9 to RHS

x = 12 -9

x = 3

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3) 3 - $\sf\dfrac{1}{4}$y = 2

3 - $\sf\dfrac{y}{4}$ = 2

Take LCM To LHS

$\sf\dfrac{12-y}{4}$ = 2

Do cross multiplication

12- y = 8

Transpose y to RHS & 8 to LHS

12 - 8 = y

y = 4

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