Question

can you guys please find the solution​

Answer 1

Step-by-step explanation:

Given:- ∴ ∠DAC=∠BAC

∠ACD=∠ACB

To prove∴ BC=BD

proof therefore In triangle ABC and triangle ADC

∠BAC=∠DAC

∠ACB=∠ACD

AC=AC

so, ΔABC≅ΔADC

=> BC=DC