Question

can you help me find this​

Answer 1

Answer:

i) 9/64         ii)   55/64

Step-by-step explanation:

i) As ΔADE and ΔABC is similar, $\frac{area-of-triangle ADE}{area-of-triangle ABC} = \frac{AD^2}{AB^2}$ = $\frac{AD^2}{(AD + DB)^2}$

AD/BD= 3/5

►AD/(AD+BD)= 3/8

so, $\frac{AD^2}{(AD + DB)^2}$  = $\frac{3^2}{8^2}$ = $\frac{9}{64}$

ii) $\frac{area-of-trapezium BCDE}{area-of-triangle ABC} = \frac{area-of-triangle ABC - area-of-triangle ADE}{area-of-triangle ABC}$ = $\frac{64-9}{64}$

= $\frac{55}{64}$