Can you help me please>?
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Answered by
2
Answer:
Given = KL = PQ = 8
om = 3 RM = 5.5
and om is the chord hence it bisect the chord
KL = 1/2KM
KL = Km = 4
To find = ok
ROM
cons= goint seg OL
find = OL =KO. ( radius of same circle ) ......1
and
by given OM is the median of seg KL
hence
in triangle KOL OM is median
by applonius theorem
OL2 + OK2 = 2KM2 + 2OM2
OL2 +OL2 = 2× (4 )2 + 2×( 3)2
2OL2 = 2× 16 + 2×9
= 32 + 18
2OL2 = 50
OL2. = 50/2
OL2 = 25
OL = 5
hence radius of circle
OK = OL = 5
( OK = 5 )
Answered by
0
Answer:
As KM is half of KL,
KM = 8/2
KM = 4 cm
So, using Pythogora's Theorem
OK^2 = 3^2 + 4^2
OK = 5
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