can You help me to find the zeroes of 4x square +5√2x-3
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4x² + 5√2x - 3 = 0
4x² + 6√2x - √2x - 3 = 0
2√2x(√2x+3) - 1(√2x+3) = 0
(√2x + 3) (2√2x - 1) = 0
=> √2x + 3 = 0
√2x = -3
x = -3/√2 (or) x = -3√2/2
=> 2√2x - 1 = 0
2√2x = 1
x = 1/2√2 (or) x = √2/4
Two zeroes are -3√2/2 and √2/4
4x² + 6√2x - √2x - 3 = 0
2√2x(√2x+3) - 1(√2x+3) = 0
(√2x + 3) (2√2x - 1) = 0
=> √2x + 3 = 0
√2x = -3
x = -3/√2 (or) x = -3√2/2
=> 2√2x - 1 = 0
2√2x = 1
x = 1/2√2 (or) x = √2/4
Two zeroes are -3√2/2 and √2/4
tejasri2:
oye
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Answered by
1
Hi Friend !!!
Here is ur answer !!!
4x²+5√2x-3
= 4x²+6√2x-√2x-3
= 2√2x(√2x+3)-1(√2x+3)
= (2√2x-1)(√2x+3)
x = 1/2√2
x = -3/√2
Hope it helps u :-)
Here is ur answer !!!
4x²+5√2x-3
= 4x²+6√2x-√2x-3
= 2√2x(√2x+3)-1(√2x+3)
= (2√2x-1)(√2x+3)
x = 1/2√2
x = -3/√2
Hope it helps u :-)
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