Question

Can you help me with this ?
(1-x) to the cube. When x= -3.

Answer 1

${(1 - x)}^{3} = 1 - {x}^{3} - 3x + {3x}^{2} \\ \\ Putting \: \: Value \: \: \: of \: \: x \\ \\ 1 - {( - 3)}^{3} - 3( - 3) + 3 {( - 3)}^{2} \\ 1 + 27 + 6 + 9 \\ 43$

Answer 2

hey mate !!!

$( {1 - x)}^{3}$

$( {1 - ( - 3)})^{3} \\ = ( {1 + 3})^{3} \\ = {4}^{3} \\ = 4 \times 4 \times 4 \\ = 64$

thus, the answer is 64.

please mark as BRAINLIEST !!!

where,

$x = - 3$

thus, putting the value