can you liquefy a van der Waals gas for which a = 0?
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✔✔ If the van der Waals constant (a) = 0 for a gas, then it behaves ideally i.e there are no intermolecular forces of attraction.
✔️✔️ So, it cannot be liquified. If a = 0, then the product of Pc and 27b2 = 0 which means that either Pc = 0 or b = 0 which is not possible.
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