Math, asked by Aastik010, 1 year ago

CAN YOU PLEASE ANSWER QUICKLY? ITS URGENT

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Answered by oliviagunda
1

Proof:

in ΔAOB and ΔCOB,

AB = BC (given)

AO = OC (radii of circle are equal)

OB = BO ( common )

by SSS,

ΔAOB ≅ΔBOC

⇒∠ABO = ∠OBC

⇒ BO bisects ∠ABC


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