Question

Can you please answer the 12 th question ??????

Answer 1

Answer:

so in this given figure it is an Quadrilateral

I) To find "x",

WKT ,

sum of the angles of an Quadrilateral = 360°

then,

2x+4° + 3x-5° + 8x - 15° + 90° = 360°

x(2+4 + 3-5 + 8-15)° + 90° = 360°

( 8 - 2 - 7)° + 90° = 360° / x

8-9 + 90 = 360/x

90° - 1° = 360°/ x

89° = 360°/x

x= 360°- 89°

x = 271°

ii) apply the value of "x"

B° = 2x + 4 = 546°

C° = 3x-5 = 808°

hope this will help you

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