Question

Can you please answer the 6 th question ?????

Answer 1

Step-by-step explanation:

AB=BD given

AC=DC given

BC=BC common

so triangle ABC is congruent to Triangle DBC by sss property

Answer 2

Answer

Your Diagram

$\setlength{\unitlength}{0.78 cm}\begin{picture}(12,4)\thicklines\put(5.6,9.1){ A }\put(5.5,5.8){ B }\put(11.1,5.8){ D }\put(11.05,9.1){ C }\put(4.5,7.5){ 10\:cm }\put(8.1,5.3){ 10 \:cm }\put(11.5,7.5){ 10 \:cm }\put(8.1,9.5){ 10\:cm }\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(6,6){\line(5,3){5}}\end{picture}$

Given

AB =BD, AC=CD

To prove

∆ABC$\cong$∆BDC

Proof

In ∆ABC and ∆BDC

AB=BD (given)

AC=CD

BC=BC (Common)

___________________

∆ABC$\cong$∆BDC. (by SSS criteria)

1. AB=CD. By cpct
2. AC = CD. By cpct
3. BC=BC common identity
4. ∆ABC$\cong$∆BDC. similarity