Question

can you please factorise 4y²+20y+25

Answer 1

4y^2+10y+10y+25
=2y(2y+5)+5(2y+5)
=(2y+5)(2y+5)
=(2y+5)^2

Answer 2

$\underline{\mathfrak{ Solution : }}$

$\mathsf{ = 4 {y}^{2} \: + \: 20y \: + \: 25 } \\ \\ \mathsf{ = (2y) ^{2} \: + \: 2 \: \times \: 2y \: \times \: 5 \: + \: ({5})^{2} }$

$\textsf{ Using Algebraic identity : } \\ \\ \boxed{ \: \mathsf{ \implies( {a}^{2} \: + \: 2ab \: + \: {b}^{2} ) \: = \: { ( a \: + \: b )}^{2} \: }}$

$\mathsf{ = (2y \: + \: 5) {}^{2} } \\ \\ \mathsf{ = (2y \: + \: 5)(2y \: + \: 5)}$

$\boxed{\underline{\mathfrak{ Hope \: \: it \: \: helps !! }}}$