Question

can you please give me the answers with steps​

Answer 1

Given

ax-3a=-12

ax=3a-12  

x=(3a-12)/a

x=3–12/a

For x to be positive the expression in RHS must always be greater than zero

x>0

3 - 12/a>0

3>12/a

a>12/3

a>4

The smallest integral value of a to satisfy this condition is a=5