can you please help me?
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Angle ABD=180-30=150.(Linear pair)
In a cyclic quadrilateral
Qngle C =180-Angle A(opposite sides are supplementary in a cyclic quadrilateral)
So,
Angle DAB = 180-70=110.
In Triangle BCD,
Angle DBC+Angle BCD+Angle BDC=180(Angle Sum Property)
30+110+Angle CDB=180
Angle CDB= 180-110-30=40.
HOPE THIS IS HELP FULL
PLEASE MARK AS A BRAINLIEST ANSWER THANK YOU
In a cyclic quadrilateral
Qngle C =180-Angle A(opposite sides are supplementary in a cyclic quadrilateral)
So,
Angle DAB = 180-70=110.
In Triangle BCD,
Angle DBC+Angle BCD+Angle BDC=180(Angle Sum Property)
30+110+Angle CDB=180
Angle CDB= 180-110-30=40.
HOPE THIS IS HELP FULL
PLEASE MARK AS A BRAINLIEST ANSWER THANK YOU
manasvini:
please mark as brainliest answer
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