Physics, asked by kechrawalabongosquad, 9 months ago

can you please help me out​

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Answered by rishabkumarsingh2000
1

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i) Equivalent Resistance :-

\frac{1}{42} Ω

ii) Currents:-

I_{40ohm} = 0.03 Ampere

I_{30ohm} = 0.03 Ampere

I_{60ohm} = 0.02 Ampere

I_{45ohm} = 0.02 Ampere

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Since,

 \frac{40}{30} = \frac{60}{45}

\frac{4}{3} = \frac{4}{3}

So, it is a special case of "WHEAT STONE BRIDGE" then, through 50 Ω resistance no current will flow.

i) Equivalent Resistance :-

\star40 Ω and 30 Ω are in series,

=> 40 Ω + 30 Ω = 70 Ω

\star60 Ω and 45 Ω are in series,

=> 60 Ω + 45 Ω = 105 Ω

Now, since 70 Ω and 105 Ω are in parallel,

=> \frac{1}{70} + \frac{1}{105} = \frac{3\:+\:2}{210}

=> \frac{5}{210}

=> \frac{1}{42} Ω

ii)  I = \frac{V}{R}

Since, in parallel combination voltage is same so, both branches will have same voltage that is 2.1 volts.

0_0 -->Since, we don’t know how much voltage is across any one of those resistors, individually.So, we will calculate using total resistance^_^ 

I_{total} = \frac{V_{total}}{R_{total}}

=> I_{total} = \frac{2.1}{70}

=> I_{total} = 0.03 Ampere

0_0 -->Since, in a series circuit, the current is the same through all of the components in the circuit^_^ 

So,

I_{40ohm} = 0.03 Ampere

I_{30ohm} = 0.03 Ampere

Similarly,

I_{total} = \frac{V_{total}}{R_{total}}

=> I_{total} = \frac{2.1}{105}

=> I_{total} = 0.02 Ampere

So, similarly

I_{60ohm} = 0.02 Ampere

I_{45ohm} = 0.02 Ampere

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