Physics, asked by kechrawalabongosquad, 8 months ago

can you please help me out​

Attachments:

Answers

Answered by rishabkumarsingh2000
1

━━━━━━━━━━━━━━━━━━━━━━━━━

━━━━━━━━━━━━━━━━━━━━━━━━━

\huge\blue{\mid{\overline{\underline{\mathbb{HELLO\:BUDDY }}}}\mid }

━━━━━━━━━━━━━━━━━━━━━━━━━

━━━━━━━━━━━━━━━━━━━━━━━━━

\maltese\Large\fbox{\color{purple}{ANSWERS}}\maltese

i) Equivalent Resistance :-

\frac{1}{42} Ω

ii) Currents:-

I_{40ohm} = 0.03 Ampere

I_{30ohm} = 0.03 Ampere

I_{60ohm} = 0.02 Ampere

I_{45ohm} = 0.02 Ampere

<html><body> <marquee Font style="z-index:2;position:absolute;left:18px;top:97px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:200px;"scrollamount="3"direction="down">❣️</marquee> <marquee Font style="z-index:2;position:absolute;left:1px;top:89px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:100px;"scrollamount="7"direction="down">❣️</marquee> <marquee Font style="z-index:2;position:absolute;left:111px;top:7px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:302px;"scrollamount="4"="4"="4"="4"="4"direction="down">Follow me</marquee> <marquee Font style="z-index:2;position:absolute;left:225px;top83px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:371px;"scrollamount="3"direction="down">❣️</marquee> <marquee Font style="z-index:2;position:absolute;left:105px;top:53px;font-family:Cursive;font-size:14pt;color:#ffcc00;height:317px;"scrollamount="2"direction="down">Follow me</marquee></body> </html>

━━━━━━━━━━━━━━━━━━━━━━━━━

\huge{\red{\tt{\underline{\underline{STEPS:-}}}}}

Since,

 \frac{40}{30} = \frac{60}{45}

\frac{4}{3} = \frac{4}{3}

So, it is a special case of "WHEAT STONE BRIDGE" then, through 50 Ω resistance no current will flow.

i) Equivalent Resistance :-

\star40 Ω and 30 Ω are in series,

=> 40 Ω + 30 Ω = 70 Ω

\star60 Ω and 45 Ω are in series,

=> 60 Ω + 45 Ω = 105 Ω

Now, since 70 Ω and 105 Ω are in parallel,

=> \frac{1}{70} + \frac{1}{105} = \frac{3\:+\:2}{210}

=> \frac{5}{210}

=> \frac{1}{42} Ω

ii)  I = \frac{V}{R}

Since, in parallel combination voltage is same so, both branches will have same voltage that is 2.1 volts.

0_0 -->Since, we don’t know how much voltage is across any one of those resistors, individually.So, we will calculate using total resistance^_^ 

I_{total} = \frac{V_{total}}{R_{total}}

=> I_{total} = \frac{2.1}{70}

=> I_{total} = 0.03 Ampere

0_0 -->Since, in a series circuit, the current is the same through all of the components in the circuit^_^ 

So,

I_{40ohm} = 0.03 Ampere

I_{30ohm} = 0.03 Ampere

Similarly,

I_{total} = \frac{V_{total}}{R_{total}}

=> I_{total} = \frac{2.1}{105}

=> I_{total} = 0.02 Ampere

So, similarly

I_{60ohm} = 0.02 Ampere

I_{45ohm} = 0.02 Ampere

━━━━━━━━━━━━━━━━━━━━━━━━━

\boxed{\underline{\green{\star{HOPE \: YOU\:GOT \:THE \:ANSWER.}}}}

\boxed{\underline{\pink{\star{MARK \: ME  \: BRAINLIEST.}}}}

\Large{\mathcal{\red{FOLLOW \: ME}}}

<marquee><font color="Red"><h1>Thankyou</marquee>

Attachments:
Similar questions