Can you PLEASE HELP ME. WILL MAKE BRAINLIEST
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Hope this helps you ☺
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Hey mate !!
Here's the answer !!
Given that, Δ ABC, Δ EDC and Δ EFG are similar to each other.
=> All the corresponding angles are equal and the corresponding sides are proportionate.
Let us find the interior angles of Δ ABC first.
We know that,
∠ DCE = ∠ ACB = 50° ( Vertically opposite angles )
Hence now in Δ ABC, ∠ A + ∠ B + ∠ C = 180°
=> 30° + ∠ B + 50° = 180°
=> ∠ B + 80° = 180°
=> ∠ B = 180° - 80° = 100°.
Hence ∠ A = 30°, ∠ B = 100°, ∠ C = 50°.
So now we can easily find the angle measures of Δ EFG.
We know that Δ ABC = Δ EFG
=> ∠ A = ∠ E
=> ∠ B = ∠ F
=> ∠ C = ∠ G
Since the corresponding angles are equal for similar triangles.
Hence ∠ E = 30°, ∠ F = 100°, ∠ G = 50°.
Hence Option ( b ) is the correct answer
Hope my answer helps !!
Cheers !!
Here's the answer !!
Given that, Δ ABC, Δ EDC and Δ EFG are similar to each other.
=> All the corresponding angles are equal and the corresponding sides are proportionate.
Let us find the interior angles of Δ ABC first.
We know that,
∠ DCE = ∠ ACB = 50° ( Vertically opposite angles )
Hence now in Δ ABC, ∠ A + ∠ B + ∠ C = 180°
=> 30° + ∠ B + 50° = 180°
=> ∠ B + 80° = 180°
=> ∠ B = 180° - 80° = 100°.
Hence ∠ A = 30°, ∠ B = 100°, ∠ C = 50°.
So now we can easily find the angle measures of Δ EFG.
We know that Δ ABC = Δ EFG
=> ∠ A = ∠ E
=> ∠ B = ∠ F
=> ∠ C = ∠ G
Since the corresponding angles are equal for similar triangles.
Hence ∠ E = 30°, ∠ F = 100°, ∠ G = 50°.
Hence Option ( b ) is the correct answer
Hope my answer helps !!
Cheers !!
Steph0303:
^_^
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