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A solid sphere of radius 5 cm floats in water. If a maximum load of 0⋅1kg can be put on it without wetting the load, find the specific gravity of the material of the sphere.
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Given,
Radius of sphere, r=5cm=0.05m
Density of sphere, ρ
s
Density of water, ρ
w
=1000kgm
−3
Volume of sphere, V=
3
4πr
3
=
3
4π×0.05
3
=
3
5π
×10
−4
m
3
Weight of water displaced, ρ
w
Vg=1000×(
3
5π
×10
−4
)×10=
3
5π
N
Weight of sphere + Load = weight of displaced water
ρ
s
Vg+0.1×10=ρ
w
Vg
ρ
s
=
Vg
ρ
w
Vg−1
Specific gravity,
ρ
w
ρ
s
=
ρ
w
Vg
ρ
w
Vg−1
=1−
ρ
w
Vg
1
=1−
3
5π
1
=0.81
Hence, specific gravity of sphere is 0.81
Answer:
1) a
2) c
3) b
4) a
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Step-by-step explanation:
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