Can you please help me with the 11th answer
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Answered by
1
Answer:
(3a+4b+2c)^2=9a^2+16b^2+4c^2+24ab+16bc+12ac
Step-by-step explanation:
Using identity,
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
(3a+4b+2c)^2=9a^2+16b^2+4c^2+24ab+16bc+12ac
PLS MARK BRAINLIEST
Answered by
0
Answer:
9a² + 16b² + 4c² + 24ab+ 16bc + 12ca
Step-by-step explanation:
We have,
(3a +4b +2c)²
using (x+y+z)² = x²+y²+z²+2(xy+yz+za) we get,
= (3a)² +(4b)² +(2c)²+ 2 [ {( 3a)(4b)} + {(4b)(2c)} + {(2c)(3a)} ]
= 9a² + 16b² + 4c² + 2(12ab+ 8bc + 6ca)
= 9a² + 16b² + 4c² + 24ab+ 16bc + 12ca
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