Math, asked by reshmakhan5115, 7 months ago

Can you please help me with the 11th answer

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Answers

Answered by amazing97
1

Answer:

(3a+4b+2c)^2=9a^2+16b^2+4c^2+24ab+16bc+12ac

Step-by-step explanation:

Using identity,

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca

(3a+4b+2c)^2=9a^2+16b^2+4c^2+24ab+16bc+12ac

PLS MARK BRAINLIEST

Answered by ZeroTerra
0

Answer:

9a² + 16b² + 4c² + 24ab+ 16bc + 12ca

Step-by-step explanation:

We have,

(3a +4b +2c)²

using (x+y+z)² = x²+y²+z²+2(xy+yz+za) we get,

= (3a)² +(4b)² +(2c)²+  2 [   {( 3a)(4b)}  +  {(4b)(2c)}  +  {(2c)(3a)}   ]

= 9a² + 16b² + 4c² + 2(12ab+ 8bc + 6ca)

= 9a² + 16b² + 4c² + 24ab+ 16bc + 12ca

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