can you please help me with this problem guys
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hi!!
let the first term be
a= 8,
d= common difference,
now,.
the formula for finding the nth term=tn= a+(n-1) ×d
now,.
t8= a+(8-1) ×d
31= a+7d...... (1)
also,
t15= a+14d and
t11= a+10d..
according to the Condition,
t15= t11+16
a+14d= a+10d+16
14d-10d= 16
4d= 16
d= 16/4=4.....(2)
now,
substituting value of d in(1),
31= a+7d
31= a+7(4)
31= a+ 28
31-28= a.
3= a
therefore,
first term = 3
common difference = 4
second term=t2= 3+4= 7
third term= t3= 7+4= 11
fourth term= t4= 11+4= 15
therefore
the AP= 3,7,11,15.......
hope this helps ❤☺✌
mickey03:
Thank you it will be very helpful
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