Question

Can you please help me with this question with a clear explanation?
Please
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Answer 1

Answer:

Sorry I didn't know what you

Answer 2

Answer:

Hope it helps you

Explanation:

Given,

Acceleration of bus, a=1ms −2

Assume man catches the train in timet.

Displacement by man in time t s 1 =vt=10t

Displacement by bus in time t, s 2 =ut+ 1/2 at² at 2 = t²/2

Separation between man and bus is 48m

s 1 =s 2 +48

10t= 2t

2 +48t

2−20t+96=0

t= 2

20± 20

2 −4×96

t=8and12

In first attempt he caches the bus

Hence, minimum time he catches the bus is 8sec