Question

can you please prove it.​

Answer 1

Answer:

Step-by-step explanation:

Firstly,

Construction..

Join XC, AC and BC..

Therefore Angle AXC = 90 degree

(angle in a semicircle), Thus, also Angle BXC = 90 degree -----------(1)

Now in ΔAXC and ΔBXC

CX = CX. (common)

angle AXC = angle BXC [From (1)]

AC = BC (radius of bigger circle)

Therefore,

Δ AXC congruent to ΔBXC

(By SAS comgruency axiom)

AX = BX (cpct)

Thus proved.....