can you please solve
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given :G is the midpoint side PQ
therefore, PG=QG...(1)
GH parallel PQ
by B. P. T
PG/GQ=PH/HR
PG/PG=PH/HR. ...(from1)
1/1=PH/HR
PH=HR
therefore by converse of midpt thm
H is the midpt of side PR
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