Math, asked by lolo43, 10 months ago

Can you please solve it step by step ​

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Answered by leninviki
1
cos x=3/5
3/5=opposite/ hypotenuse
3^2+(a)^2=5^2
a^2=25-9
a=4

tan x=4/3 Cosec x= 5/4 sec x =5/3 cot x=3/4

numerator 5*5/4-4*4/3= 25/4 - 16/3=(75-64)/12=11/12

denominator sec x+ cot x=5/3+3/4=(20+9)/12=29/12

(11/12)/(29/12)=11/29

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