Math, asked by PekaPachuau31, 6 months ago

can you please solve.......no spam answer needed....
this is my exam questions.​

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Answers

Answered by nandika32
1

Answer:

Answer........................ 5th question

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Answered by Saby123
4

Solution:

Question 5 -

a + b√3 = ( √3 + 1)/( √3 - 1)

We need to first rationalise the RHS .

This can be done by multiplying both sides ( the numerator and denominator ) with (√3+1) .

a + b√3

=> [ √3 + 1]/[ √3 - 1] × [ √3 +1 ]/[ √3 + 1]

=> ( √3 + 1)²/2

=> ( 3 + 1 + 2√3 )/2

=> 4 + 2√3/2

=> 2 + √3

Comparing this , we get :

a = 2

b = 1.

Question 6 :

x = (√3+√2 )/( √3 - √2 )

y = ( √3 - √2 )/( √3 + √2 )

x = (√3+√2 )/( √3 - √2 )

=> [ √3 + √2 ]^2

y = inverse of x

=> [ √3 - √2 ]^2

x + y

=> ( √3 + √2)² + (√3 - √2 )²

=> 5 + 5

=> 10 .

This is the required answer .

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