Question

can you please solve the given question​

Answer 1

Answer:

Hii mate your solution ❤❤

Answer 2

SOLUTION

cosec A+ cot A= p.......(1)

Now,

$= > cosec {}^{2} </strong><strong>A</strong><strong>- cot {}^{2} </strong><strong>A</strong><strong>= 1$

=)(cosec A+ cot A)(cosec A- cot A)= 1

=)p(cosec A - cot A)= 1

=) cosec A- cot A= 1/p........(2)

Adding (1) & (2), we get

$= > 2 \: cosec \: </u></strong><strong><u>A</u></strong><strong><u> = p + \frac{1}{p} \\ = > cosec \: </u></strong><strong><u>A</u></strong><strong><u> = \frac{ {p}^{2} + 1 }{2p} \\ = > sin \: </u></strong><strong><u>A</u></strong><strong><u> = \frac{1}{cosec \: </u></strong><strong><u>A</u></strong><strong><u>} = \frac{2p}{ {p}^{2} + 1} \\ \\ = > cos \: </u></strong><strong><u>A</u></strong><strong><u> = \sqrt{1 - {sin}^{2} } </u></strong><strong><u>A</u></strong><strong><u> = \sqrt{1 - \frac{4 {p}^{2} }{( {p}^{2} + 1) {}^{2} } } = \sqrt{ \frac{ {p}^{4} + 1 - 2 {p}^{2} }{( {p}^{2} + 1) {}^{2} } } \\ \\ = > \sqrt{ \frac{( {p}^{2} - 1) {}^{2} }{( {p}^{2} + 1) {}^{2} } } = \frac{ {p}^{2} - 1}{ {p}^{2} + 1 }$

hope it helps ☺️