can you please solve these problems
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Let the 3 terms be a-d,a,a+d
Given:a-d+a+a-d=33
3a=33
a=33/3=11
(a-d)(a+d)=a+29
a²-d²=a+29
11²-d²=11+29
121-d²=40
121-40=d²
81=d²
d=√81
d=9
A.P:a-d,a,a+d
:11-9,11,11+9
:2,11,20
Given:a-d+a+a-d=33
3a=33
a=33/3=11
(a-d)(a+d)=a+29
a²-d²=a+29
11²-d²=11+29
121-d²=40
121-40=d²
81=d²
d=√81
d=9
A.P:a-d,a,a+d
:11-9,11,11+9
:2,11,20
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