can you please solve these two parts
Attachments:
Answers
Answered by
1
Answer:
1) t= 10
2) x= (-3)
Step-by-step explanation:
1) ³√2-t = ³√2t-28
(cube on both side)
( ³√2-t)³ = ( ³√2t-28)³
(cube and cube root gets cancelled)
2-t = 2t-28
2+28 = 2t+t
30 = 3t
t = 30/3
t = 10
2) (square both sides)
x+1/2x+5 = 2
transpose (2x+5) to RHS
x+1 = 2(2x+5)
x+1 = 4x+10
-10+1 = 4x-x
-9 = 3x
x= -9/3
x = -3
hope it helped you.......
Answered by
0
Step-by-step explanation:
Yeah I can solve these two parts
Similar questions