Question

Can you please solve this?
12a2b-16ab2-28a2b2
thanks!

Answer 1

Answer:

4ab (3a-7ab-4b)

Step-by-step explanation:

This sum is an example of factorization by splitting the middle term

12a2b-16ab2-28a2b2

=12a2b-28a2b2-16ab2

=12a2b-12a2b2-16a2b2-16ab2

(12x-16= -192. the factors -of 192 that are -16 and -12 make -28 and hence those factors are used)

=4ab (3a-3ab-4ab-4b)

=(4ab (3a-7ab-4b)

Hope this helps :)