Question

can you please solve this
√2(sinx+cosx) = √3

Answer 1

Step-by-step explanation:

Given:

√2(sinx + cosx) = √3

Squaring both the sides

2(sinx+cosx)^2 = 3

or (sinx +cosx)^2 = 3/2

or sin^2 x + cos^2x +2SinxCosx = 3/2

or 1 + 2SinxCosx = 3/2

or 2 SinXCosX = 3/2 -1

or 2SinxCosX = 3-2/2

or 2 SinXCosX = 1/2.....(1)

Now LHS = √2(sinx + cosx)

or 2(sinx+cosx)^2

or 2(sin^2x + cos^2x +2SinxCosx)

or 2(1+ 2SinxCosx)

or 2 + 4SinXCosX

or 2 + 2(2SinxCosx)

or 2 + 2(1/2) (from 1)

or 2 +1 = 3 = RHS....... Answer

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