Question

Can you please solve this :



8−i3−2i

If the expression above is rewritten in the form a+bi, where a and b are real numbers, what is the value of a? (Note: i=−1)

Answer 1

Answer:

Step-by-step explanation:

So you are asking for Re(8−3−2)

First problem is, we haven’t got something which looks like a+bi here, so we have to simplify (8-i)/(3–2i).

Multiply numerator and denominator by the conjugate of the latter:

8−3−2=(8−)(3+2)13

Simplify:

=26+1313=2+

So Re(8−3−2)=Re(2+)=2