can you please solve this
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Step-by-step explanation:
Let the natural positive number be x
ATQ
x + 84 = 160 ( 1/x)
x² + 84x = 160
x² + 84x - 160 = 0
Here a quadratic equation formed :
Where
a (coefficient of x²) = 1
b (coefficient of x ) = 84
c (constant ) = -160
D (Discriminant ) = b² - 4ac
= 84² - 4 x 1 x 160
= 7056 + 640
= 7696
we are finding roots (zeros) of the quadratic by this quadratic formula
-b+-√D/2a
Two zeros are
160 - √7696 / 2 and 160 + √7696 / 2
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Answer:
The answer given below is right
Step-by-step explanation:
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