Question

Can you please solve this question. If any user answered it correctly than I will make it brainlist​

Answer 1

Here is the answer...

Hope it helps!!!

Plz mark as brainliest...

Answer 2

$\bold\red{\underline{\underline{Answer:}}}$

$\bold{=>2(a^{2}-\frac{1}{a^{2}})}$

$\bold\blue{Explanation}$

$\bold{a^{2}+b^{2}=(a+b)^{2}-2ab}$

$\bold\orange{Given:}$

$\bold{(a-\frac{1}{a})^{2}+(a+\frac{1}{a^{2}})}$

$\bold\green{\underline{\underline{Solution}}}$

$\bold{By \ identity \ a^{2}+b^{2}=(a+b)^{2}-2ab}$

$\bold{=>(a-\frac{1}{a}+a+\frac{1}{a})^{2}-2[(a-\frac{1}{a})(a+\frac{1}{a})]}$

$\bold{=>(2a)^{2}-2(a^{2}-\frac{1}{a}^{2})}$

$\bold{=>4a^{2}-2a^{2}-\frac{2}{a^{2}}}$

$\bold{=>2a^{2}-\frac{2}{a^{2}}}$

$\bold{=>2(a^{2}-\frac{1}{a^{2}})}$