Question

Can you pls answer fast any one pls don’t answer I don’t and other stuff pls answer properly

Answer 1

Step-by-step explanation:

given 3x-5y+2z-(x-4y-7z)=

=3x-5y+2z-x+4y+7z

=2x-y+9z if x=-1,y=0,z=2

=2(-1)-0+9(2)

=-2+18

=16

Answer 2

Question :-

Subtract 3x - 5y + 2z from x - 4y - 7z.

Find the value of difference if x = -1 , y = 0 and z = 2

Answer :-

To solve this problem, we first need to subtract 3x - 5y + 2z from x - 4y - 7z and then simply substitute the value of x , y and z as -1 , 0 and 2 respectively.

$\rm x - 4y - 7z - (3x - 5y + 2z)$

$\rm = x - 4y - 7z - 3x + 5y - 2z$

$\rm = x - 3x - 4y + 5y - 7z - 2z$

$\rm = -2x + y - 9z$

Substituting the values of x , y and z -

$\rm -2x + y - 9z = -2 (-1) + 0 - 9 (2)$

$\rm = 2 + 0 - 18$

$\boxed{\rm = - 16}$

Question :-

Find the sum of a² - 7ab + b² and 8ab - 7b² - 3a². Find the value of sum if a = 1, b = 1.

Answer :-

Firstly we will add a² - 7ab + b² and 8ab - 7b² - 3a² and then substitute the value of a and b as 1 and 1 respectively.

$\rm a^2 - 7ab + b^2 + 8ab - 7b^2 - 3a^2$

$\rm = a^2 - 3a^2 - 7b^2 + b^2 + 8ab - 7ab$

$\rm = -2a^2 - 6b^2 + ab$

Substituting the values of a and b -

$\rm = -2 (1)^2 - 6 (1)^2 + 1 \times 1$

$\rm = -2 - 6 + 1$

$\rm = -8 + 1$

$\boxed{\rm = -7}$