Can you pls solve this question....
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Hii There!!!
It's simple....
See..
Here [ -1/3 ] is the zero of given polynomial p(x)
So, on substituting x = [ -1/3 ] we get ;
p ( -1/3 ) = 27 × ( -1/3 )^3 - a × ( -1/3 )^2 - ( -1/3 ) + 3 = 0
=> 27 × [ - 1/27 ] -a × 1/27 + 1/3 + 3 = 0
=> -1 - a/27 + 1/3 + 3 = 0
=> - 27 - a whole divided by 27 + 10/3 = 0
=> -27 - a + 90 whole divided by 27
=> - 27 - a + 90 = 0
=> -a + 63 = 0
=> - a = -63
Negative sign will be cancelled out
So, we get a = 63
Hence, the value of 'a' will be 63
_____________________
# ¢'$ #
Hope it helps :)
It's simple....
See..
Here [ -1/3 ] is the zero of given polynomial p(x)
So, on substituting x = [ -1/3 ] we get ;
p ( -1/3 ) = 27 × ( -1/3 )^3 - a × ( -1/3 )^2 - ( -1/3 ) + 3 = 0
=> 27 × [ - 1/27 ] -a × 1/27 + 1/3 + 3 = 0
=> -1 - a/27 + 1/3 + 3 = 0
=> - 27 - a whole divided by 27 + 10/3 = 0
=> -27 - a + 90 whole divided by 27
=> - 27 - a + 90 = 0
=> -a + 63 = 0
=> - a = -63
Negative sign will be cancelled out
So, we get a = 63
Hence, the value of 'a' will be 63
_____________________
# ¢'$ #
Hope it helps :)
Khushi0511:
Actually there is no option to edit my ans. now
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