Question

can you plz give the answer step wise

Answer 1

AP=BP=PC
<ABC = 1 RIGHT ANGLE
AS (AP+PC)=AC
THEN BP IS HALF OF THE AC
THAT'S WHY BP IS PERPENDICULAR TO AC
PROVED THAT <ABC = RIGHT ANGLE

HOPE IT WILL HELP YOU

Answer 2

●•••••••••• Hello User •••••••••●
《《 Here is your answer 》》
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In triangle APB

: AP = BP

then , Base angles of a triangle having two equal side are also equal ,

/BAP = /ABP ...... let /ABP = x
/BAP = x

Now ,

In triangle CPB

: CP = BP

then , Base angles of a triangle having two equal side are also equal ,

/BCP = /CBP ...... as /BCP = x
/CBP = x

Now ,

In triangle ABC sum of all angles is 180°

/BAC + /ABC + /BCA = 180°

/BAP + ( /ABP + /CBP ) + /BCP = 180°
....... as /BAC = /BAP
............ /ABC = ( /ABP + /CBP )
............ /BCA = /BCP

x + ( x+x ) + x = 180°
4x = 180°
x = 45°

Now,

= /ABC
= ( /ABP + /CBP )
= x + x
= 45° + 45°
= 90° .....proved

:./ABC = 90°.
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《《 Hope it may helpful to you 》》

•••••• @ajaman ^_^ ••••••
●••••• ☆ Brainly Star ☆ •••••●