Question

can you plz solve this ​

Answer 1

Answer:

$\frac{ \sqrt{6} }{ \sqrt{2} + \sqrt{3} }$

$\frac{ \sqrt{6} }{ \sqrt{2} + \sqrt{3} } \times \frac{ \sqrt{2} - \sqrt{3} }{ \sqrt{2} - \sqrt{3} }$

$\frac{ \sqrt{12 } - \sqrt{18} }{ - 1}$

$- 2 \sqrt{3 +} 3 \sqrt{2}$