Question

can you show me how its done,i'm quite lost at some point .

Answer 1

Step-by-step explanation:

its easy

refer pic

pls thank follow and mark as brainliest

Answer 2

$\implies \sf \: \dfrac{ \cos^{2} (\theta) }{1 - \tan(\theta) } + \dfrac{ \sin ^{3} (\theta) }{ \sin(\theta) - \cos(\theta) } \\ \\ \implies\frac{ \ \cos^{2} (\theta) }{1 - \dfrac{ \sin(\theta) }{ \cos(\theta) } } + \frac{ \sin^{3} (\theta) }{ \sin(\theta ) \cos(\theta) } \\ \\ \implies\frac{ \cos^{2} (\theta) }{ \dfrac{ \ \cos(\theta) - \sin(\theta) }{ \cos(\theta) } } + \frac{ \sin^{3} (\theta) }{ \sin(\theta ) - \cos(\theta) } \\ \\ \implies\frac{ \cos^{3} (\theta) }{ \cos(\theta) - \sin(\theta) } + \frac{ \sin^{3} (\theta) }{ \sin(\theta ) - \cos(\theta) } \\ \\ \implies\frac{ \cos^{3} (\theta) }{ \cos(\theta) - \sin(\theta) } - \frac{ \sin^{3} (\theta) }{ \cos (\theta ) - \sin(\theta) } \\ \\ \implies\frac{ \cos^{3} (\theta) - \sin^{3} (\theta) }{ \cos(\theta) - \sin(\theta) } \\ \\ \implies\frac{ \cancel{(\cos(\theta) - \sin(\theta) )}( \cos ^{2}(\theta) + \sin ^{2} (\theta) + 2. \sin(\theta). \cos(\theta) ) }{ \cancel{\cos(\theta) - \sin(\theta)} } \\ \\ \implies1 + 2 \sin(\theta) \cos(\theta)$

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in the last 5th step I have taken -ve sign common in order to make the denominators same.

I hope this helps uh