Question

Can you show me how to solve this?

Answer 1

x2 -16

(x)2-(4)

(x+4)(x-4)

(x+4)(x+2)(x-2)

Answer 2

It is easy just use

${x}^{2}-{y}^{2}={(x+y)}{(x-y)}$

${x}^{2} - 16 \\ = ( {x)}^{2} - ( {4)}^{2} \\ = (x - 4)(x + 4) \\ = > x - 4 = 0 \\ x = 4 \\ = > x + 4 = 0 \\ x = - 4$