Question

can you solve 17 no question​

Answer 1

Answer

value of k = 3,

Given

(k,-2), (1,4), (-3,16) points are collinear.

To Find

value of k.

Solution

$condition \: for \: collinear \: points \\ \\ x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2) = 0$

WHERE,

$\: x1 = k, \: x2 = 1, \: x3 = - 3, \: y1 = - 2, \: y3 = 16$

k (-4-16)+ 1 [16-(-2)]+ (-3) (-2-4) =0

-12k+18+18= 0

-12k+ 36= 0

12k= 36

$k = \frac{36}{12} = 3$