Question

Can you solve for x where = 7^2x+1 / 49=7^-3

Answer 1

Hey mate

So according to the question

${7}^{2}x + 1 \div 49 = {7}^{ - 3 } \\ {7}^{2}x + 1 \div {7}^{2} = 1 \div {7}^{3} \\ \\ {7}^{2} x + 1 = 1 \div 7 \\ {7}^{3} x + 7 = 1 \\ x = - 6 \div 243$