can you solve it wit proof
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Given BA || ED and BC || EF.
To show ∠ABC = ∠DEF.
Construction Draw a ray EP opposite to ray ED.
proof in the figure BA || ED or BA || DP
therefore ∆ABP=∆EPC
∆ABC=EPC
again BC||EF or PC|| EF
∆DEF=∆EPC
from 1 and 2 equations
∆ABC=∆DEF=180°
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