Can you solve of homogeneous differential equations dy/dx=y³-2y²x-yx²/yx²+x³ i very need the solve..
Answers
Answered by
0
Answer:
yx^2.dx=(x^3+y^3)dy
dy/dx=yx^2/(x^3+y^3) , let y=v.x
dy/dx=v.1+x.dv/dx
v+x.dv/dx=vx^3/(x^3+v^3.x^3)
v+x.dv/dx=v/(1+v^3)
x.dv/dx=v/(1+v^3) -v=(v-v-v^4)/(1+v^3)
x.dv/dx= -v^4/(1+v^3)
(1+v^3)/v^4.dv=-1/x.dx
[(1/v^4)+(1/v)].dv= -1/x.dx , integrate both side
-4.(1/v^5)+log v=-log x+C
log v+log x=C+4/v^5
logv.x=C+4/v^5
v.x=e^(C+4/v^5) , put v=y/x
y=e^(C+4.x^5/y^5) , Answer
*answer not owned*
Step-by-step explanation:
Similar questions