Can you solve question 32?
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According to mirror formula-
1/f = 1/v + 1/u where f = focal length, v = image distance, u = object distance
v = -10 cm (as object is on left side)
u = -15 cm (as image formed is also on left side)
Therefore, 1/f = -1/10 + (-1/15)
1/f = -1/6
f = -6cm
1/f = 1/v + 1/u where f = focal length, v = image distance, u = object distance
v = -10 cm (as object is on left side)
u = -15 cm (as image formed is also on left side)
Therefore, 1/f = -1/10 + (-1/15)
1/f = -1/6
f = -6cm
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Focal length of the mirror is -6 cm.
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