Can you solve that problem
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7+6+9
______=11cm
2
Area of triangle 11(11-7)(11-6)(11-9)=440Cm2
Now in triangle inADC Having side 15cm,12cm and 9cm,we have
s=15+12+9
________=18cm
2
18(18-15)(18-12)(18-9)
=54cm2
There the area of quadrilateral ABCD=
____
\440+54)cm2
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