Question

can you solve the given question ❓​

Answer 1

Answer:

hope it will help you friend

Answer 2

$\huge \fcolorbox{red}{lime}{ \red{y = 2}}$

Step-by-step explanation:

$5y - \frac{1}{3} (y + 1) = \frac{2y + 8}{3} + 5 \\ \\ = > 5y - \frac{1}{3} y - \frac{1}{3} = \frac{2y + 8 + 15}{3} \\ \\ = > y( 5 - \frac{1}{3} ) - \frac{1}{3} = \frac{2y + 23}{3} \\ \\ = > y( \frac{15 - 1}{3} ) - \frac{1}{3} = \frac{2y + 23 }{3} \\ \\ = > \frac{14y}{3} - \frac{1}{3} = \frac{2y + 23}{3} \\ \\ = > \frac{14y - 1}{3} = \frac{2y + 23}{3} \\ \\ = > 14y - 1 = \frac{2y + 23}{ \cancel{3}} \times \cancel{3} \\ \\ = > 14y - 1 = 2y + 23 \\ \\ = > 14y - 2y = 23 + 1 \\ \\ = > 12y = 24 \\ \\ = > y = \frac{ \cancel {24}^{ \: 2} }{ \cancel{12}} \\ \\ = > y = 2$

Hence ths value of y = 2.

hope it helps.