Can you solve the problem and explain?
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(a) Xi = m
Yi = m
(b) Vix = m/s
viy = m/s
(c) Particle under constant speedparticle under constant, nonzero acceleration
(d) particle under constant speedparticle under constant, nenzero acceleration.
(e) Vfx =
vfy =
(f) xf =
yf =
(g) S
(h) V = m/s
?= ॰ counterclockwish from the cliff and throw a stone horizonatally over the edge with a speed of
Vi = 22.5 m/s
The cliff is
h = 41.2 m
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