Question

Can you solve this
1+4=5, 2+5=12, 3+6=21, 8+11=96
Then 7+8=?

Answer 1

Answer :

63

Given :-

1+4=5,

2+5=12,

3+6=21,

8+11=96

To find :-

Find 7+8 ?

Solution :-

Given that:

1)1+4 can be written as

=> 1×4+1

=> 4+1

=> 5

So, 1+4 = 5

2) 2+5 can be written as

=> 2×5+2

=> 10+2

=> 12

So, 2+5 = 12

3) 3+6 can be written as

=> 3×6+3

=> 18+3

=> 21

So, 3+6=21

4)8+11 can be written as

=> 8×11+8

=> 88+8

=> 96

So, 8+11=96

Now,

5)7+8 can be written as

=> 7×8+7

=> 56+7

=> 63

So, 7+8=63

Answer:-

7+8=63 for the given problem

Used Pattern formula:-

Product of two numbers+ First number