can you solve this
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✧ The given sequence are in AP .
Because the common difference is same .
✧Sn =n/2 [2a+(n-1)d]
✧14 terms of the sequence is taken , so that their sum is 70
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Answer:
sequence contain 14 terma to get sum 70
Step-by-step explanation:
GIVEN:-
Sn=70
a=-8
d=-6-(-8)=-6+8=2
n=??
solution:-
Sn=n/2 {2a+(n-1)d}
70=n/2 {2×-8+(n-1)×2)
140=n{-16+2n-2}
140=n{-18+2n}
140=-18n+2n²
2n²-18n-140=0
by dividing eq∧n by 2
we get,,
n²-9n-70=0
by solving this quadratic equation
n= -5 or 14
∵n can never be negative
∴n=14
∴the sequence contain 14 terma to get sum 70
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