can you solve this 6th grade problem ?? Give proper solution.
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Anonymous:
never saw such question in any 6 grade book lol haha
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good question hope this helps u
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According to the symmetrical geometry , If we combine both the parts of the circle which are present downside, We will get a perfect circle,
So now we can find the area of red part by, Subtracting Area of Circle from Area of triangle,
Area of triangle = 1/2 * base * height,
=> 1/2* 20 * 10 = 100,
Area of Circle = πr²,
=> π(5²) since radius = height /2,
=> 25 π is the area of Circle,
=> Area of red region = 100 - 25π = 21.460(Approximately),
Also we can do this problem in another way,
By the way this is the shortcut method, So I told you this, If you need alternative solution inbox me,
And btw this question was asked in China,
Hope you understand, Have a great day !
So now we can find the area of red part by, Subtracting Area of Circle from Area of triangle,
Area of triangle = 1/2 * base * height,
=> 1/2* 20 * 10 = 100,
Area of Circle = πr²,
=> π(5²) since radius = height /2,
=> 25 π is the area of Circle,
=> Area of red region = 100 - 25π = 21.460(Approximately),
Also we can do this problem in another way,
By the way this is the shortcut method, So I told you this, If you need alternative solution inbox me,
And btw this question was asked in China,
Hope you understand, Have a great day !
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